It will work but not recommended as the tone will change since the reflected impedance back to the tubes will be different . The power tubes will not deliver per design. The Tweed has an 8K / 8 ohm OT, so in this case, a 16 ohm speaker will reflect back 16K to the tubes which will stifle the sound.
Use two in parallel!
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Reflected Impedance
A tube is a high-voltage/low-current (high-impedance) device, while a speaker is a low-voltage/high-current (low-impedance) device. The function of the audio output transformer is to transform the high impedance of the output tube to match the much lower impedance of the speaker. This is necessary to get an efficient transfer of the audio signal to the speaker. The output transformer as an impedance matching device, works on the principal of reflected load. To help explain this, refer to figure 1 below.
To keep the math simple, lets assume an output tube is supplying a 100 volt ac signal to the primary of an output transformer with a 10:1 winding ratio, and the secondary is feeding a 10 ohm voice coil (see figure 1A below). With 100 volts across the primary, there will be 10 volts across the voice coil connected to the secondary. Using ohms law, there will be 1 amp of current flowing in the voice coil.
I = E/R
I = 10/10 = 1 ampere
For further simplification we will assume 100% efficiency in the transformer. Since we have a 10:1 ratio, the current flowing in the primary will be .1 ampere ( 1 amp in secondary divided by 10). With 100 volts across the primary, ohms law tells us that the primary looks like a 1,000 ohms impedance load to the tube.
Z = E/I
Z = 100/.1 = 1,000 ohms
Now if we decrease the impedance of the load, what happens to the impedance in the primary? If we place another 10 ohm voice coil in parallel with the original one, we now have a 5 ohm load (see figure 1B below). Using ohms law again we see that the current in the secondary is now 2 amperes.
I = E/R
I = 10/5 = 2 amperes
This means that the current in the primary also doubles to .2 amperes. Again using ohms law, the impedance of the primary is now 500 ohms.
Z = E/I
Z = 100/.2 = 500 ohms
This is called the reflected load. A 10 ohm load reflects back a 1,000 ohm impedance, while a 5 ohm load reflects back a 500 ohm impedance. The reflected impedance is a function of the turns ratio of the transformer.
from "Radio Remembered"